document.write( "Question 304822: A rectangular field is to enclosed with 600 m of fencing. What dimensions will produce a maximum area? \n" ); document.write( "
Algebra.Com's Answer #218326 by checkley77(12844)\"\" \"About 
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2X+2Y=600
\n" ); document.write( "X+Y=300
\n" ); document.write( "X=300-Y
\n" ); document.write( "XY=(300-Y)Y
\n" ); document.write( "300Y-Y^2
\n" ); document.write( "Y^2-300+22,500=22,500 COMPLETING THE SQUARE.
\n" ); document.write( "(Y-150)^2=22,500
\n" ); document.write( "Y=150 ANS. FOR THE SIDES OF THE SQUARE WITH AN AREA OF 22,500.
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