document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=35706>Question 35706</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a radio tower casts a shadow 120 meters long when the angle of elevation of the sun is 41 (degrees. how tall is the tower? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21829 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21829\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Draw a picture of a tower of height x, that is perpendicular to the ground.  The shadow is on the ground at a distance of 120 meters.  This one requires trigonometry, where <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan+41+=+%28opposite%29%2F%28adjacent%29+=+x%2F120 ALIGN=MIDDLE  ALT=\"tan+41+=+%28opposite%29%2F%28adjacent%29+=+x%2F120\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Therefore <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x+=+120%2A+tan+41 ALIGN=MIDDLE  ALT=\"+x+=+120%2A+tan+41\"   DISABLED_style= \"max-width:90%; height:auto;\" > degrees.  Be sure your calculator is in degree mode and calculate:  x = 104.31 meters.\r<BR>\n" );
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document.write( "R^2 at SCC  </SPAN>\n" );
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