document.write( "Question 304802: what has the least value. 0.27, 1/4, 3/8, 2/11, 11% \n" ); document.write( "
Algebra.Com's Answer #218283 by Edwin McCravy(20055) $\"\"$ $\"About$
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0.27, 1/4, 3/8, 2/11, 11%
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document.write( "Change them all to fractions:\r\n" );
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document.write( " means the fraction \r\n" );
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document.write( " is already a fraction\r\n" );
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document.write( " is already a fraction \r\n" );
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document.write( " is already a fraction \r\n" );
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document.write( " means the fraction \r\n" );
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document.write( "Now we line up the five fractions:\r\n" );
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document.write( ", , , , \r\n" );
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document.write( "We get the LCD of all these, \r\n" );
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document.write( "100=2*2*5*5\r\n" );
document.write( "4 = 2*2\r\n" );
document.write( "8 = 2*2*2\r\n" );
document.write( "11= 11\r\n" );
document.write( "100=2*2*5*5\r\n" );
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document.write( "So the LCD must contain each factor the most number of times it\r\n" );
document.write( "occurs as a factor in any one of those, so the LCD must contain \r\n" );
document.write( "2 three times, because 2 occurs at most three times as a factor \r\n" );
document.write( "in 8. It must contain 5 two times because 5 occurs twice as a \r\n" );
document.write( "factor in 4 and 100, and it must contain 11 one time since 11 \r\n" );
document.write( "occurs at most one time in 11 itself.\r\n" );
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document.write( "So LCD=2*2*2*5*5*11=2200.\r\n" );
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document.write( "Now write them all with the common denominator of 2200:\r\n" );
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document.write( "The smallest of these is the one with the smallest\r\n" );
document.write( "numerator (when expressend with the same common\r\n" );
document.write( "denominator):\r\n" );
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document.write( "So  is the smallest of the five.\r\n" );
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document.write( "You might find it easier to convert them all to decimals\r\n" );
document.write( "instead of fractions:\r\n" );
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document.write( " is already a decimal  \r\n" );
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document.write( " \r\n" );
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document.write( "  \r\n" );
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document.write( "The smallest has the smallest tenths digit.\r\n" );
document.write( "The  and  both have smallest tenths \r\n" );
document.write( "digits of 1.  So it's between those two.  So we go for the \r\n" );
document.write( "one of those two with the smaller hundredths digit, and the \r\n" );
document.write( "hundredths digit of  is 1 while the hunmdredths \r\n" );
document.write( "digit of  is 8. So the smallest of the five is\r\n" );
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document.write( "Edwin
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