document.write( "Question 304792: How many farther can a boa traveling at a rate of 15 kilometers per hour for x hours travel than a second boat traveling at a rate of 18 kilometers per hour for x-3hours? \n" ); document.write( "
Algebra.Com's Answer #218271 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How much farther can a boat traveling at a rate of 15 kilometers per hour for x hours travel than a second boat traveling at a rate of 18 kilometers per hour for x-3hours? \n" ); document.write( "--- \n" ); document.write( "Distance = rate*time \n" ); document.write( "1st: 15x miles \n" ); document.write( "2nd: 18(x-3) = 18x-54 \n" ); document.write( "------------------------------- \n" ); document.write( "Equation: \n" ); document.write( "(18x-54) - 15x = 3x-54 miles further. \n" ); document.write( "===================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================================== \n" ); document.write( " \n" ); document.write( " |