document.write( "Question 304771: Bill is 3 times as old as Nancy.\r
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document.write( "In 12 years Bill will be twice as old as Nancy.\r
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document.write( "How old are Bill and Nancy now? \n" );
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Algebra.Com's Answer #218245 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Bill is 3 times as old as Nancy. \n" ); document.write( "In 12 years Bill will be twice as old as Nancy. \n" ); document.write( "How old are Bill and Nancy now? \n" ); document.write( "----------------- \n" ); document.write( "Equations: \n" ); document.write( "b = 3n \n" ); document.write( "(b+12) = 2(n+12) \n" ); document.write( "------------------- \n" ); document.write( "Substitute for \"b\" and solve for \"n\": \n" ); document.write( "3n+12 = 2n+24 \n" ); document.write( "n = 12 yrs old (Nancy's age now) \n" ); document.write( "--- \n" ); document.write( "Since b = 3n, b = 3*12 = 36 yrs old (Bill's age now) \n" ); document.write( "====================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============================== \n" ); document.write( " |