document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=304765>Question 304765</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Angles P and Q are complimentary. If mLP = x, and mLq = x+10, find the measure of each angle. Help please show the work. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218243 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218243\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     Angles P and Q are complimentary. If mLP = x, and mLq = x+10, find the measure of each angle. Help please show the work.<BR>\n" );
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document.write( "If two angles are complementary, this means that the sum of the two angles equals 90 degrees.<BR>\n" );
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document.write( "This must mean that<BR>\n" );
document.write( "x + x+10 = 90<BR>\n" );
document.write( "2x+10 = 90<BR>\n" );
document.write( "2x = 80<BR>\n" );
document.write( "x = 40<BR>\n" );
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document.write( "So:<BR>\n" );
document.write( "mLP = x = 40 degrees<BR>\n" );
document.write( "mLq = x+10 = 40+10 =50 degrees </SPAN>\n" );
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