document.write( "Question 304715: The ancient Greeks thought that the most pleasing shape for a rectangle was one for which the ratio of the length to the width was approximately 8 to 5, the golden ratio. If the length of a rectangular painting is 2 ft. longer than its width, then for what dimensions would the length and width have the golden ratio? \n" ); document.write( "
Algebra.Com's Answer #218241 by ankor@dixie-net.com(22740)\"\" \"About 
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the most pleasing shape for a rectangle was one for which the ratio of the length
\n" ); document.write( "to the width was approximately 8 to 5, the golden ratio.
\n" ); document.write( " If the length of a rectangular painting is 2 ft. longer than its width,
\n" ); document.write( " then for what dimensions would the length and width have the golden ratio?
\n" ); document.write( ":
\n" ); document.write( "let x = the width
\n" ); document.write( "then
\n" ); document.write( "(x+2) = the length
\n" ); document.write( ":
\n" ); document.write( "\"%28x%2B2%29%2Fx\" = \"8%2F5\"
\n" ); document.write( "cross multiply
\n" ); document.write( "8x = 5(x+2)
\n" ); document.write( "8x = 5x + 10
\n" ); document.write( "8x - 5x = 10
\n" ); document.write( "3x = 10
\n" ); document.write( "x = \"10%2F3\"
\n" ); document.write( "x = 3\"1%2F3\" ft is the width, then 5\"1%2F3\" ft is the length, the golden ratio
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