document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=304738>Question 304738</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 30 % of firm’s orders come from new customers. A simple random sample of 100 orders will be used to estimate the proportion of new customers. Find probability that sample proportion will be between 0.22 and 0.40 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218224 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218224\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 30 % of firm’s orders come from new customers. A simple random sample of 100 orders will be used to estimate the proportion of new customers. Find probability that sample proportion will be between 0.22 and 0.40<BR>\n" );
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document.write( "p = 0.3<BR>\n" );
document.write( "sigma = sqrt(pq) = sqrt(0.3*0.7)<BR>\n" );
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document.write( "z(0.22) = (0.22-0.30)/[sqrt(0.3*0.7/100)] = -1.7457<BR>\n" );
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document.write( "z(0.40) = (0.40-0.30)/[sqrt(0.3*0.7/100)] = 2.1822<BR>\n" );
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document.write( "P(0.22 < p < 0.40) = P(-1.7457 < z < 2.1822) = 0.9450<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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