document.write( "Question 304724: Rewrite the linear equations as a function of x.
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document.write( "-2x+3y=11 \n" );
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Algebra.Com's Answer #218214 by Theo(13342)![]() ![]() You can put this solution on YOUR website! Equation is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-2x+3y=11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add 2x to both sides of the equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3y = 2x + 11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide both sides of the equation by 3 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = (2/3)*x + (11/3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let y = f(x) to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f(x) = (2/3)*x + (11/3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "What you get is y equals a function of x which is equal to the expression (2/3)*x + (11/3).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x is the argument of the function.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x is the independent variable.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f(x) is the dependent variable.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since y = f(x), y is also the dependent variable.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |