document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=304487>Question 304487</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40mph and train B is traveling at 48 mph.  Train A passes a station at 7:20am.  If Train B passes the same station at 7:35am, at what time will train B catch up with train A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218205 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218205\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A has a 15 minute head start. How far can a go in15 minutes?<BR>\n" );
document.write( "40*1/4=10miles<BR>\n" );
document.write( "train b is gaining on a at 8 mph\r<BR>\n" );
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document.write( "so it will take b r*t=d<BR>\n" );
document.write( "t=d/r<BR>\n" );
document.write( "t=10/8 to catch up<BR>\n" );
document.write( "1 1/4 hour<BR>\n" );
document.write( "add 1:15 to 7:35<BR>\n" );
document.write( "8:50 train b acatches train a<BR>\n" );
document.write( " </SPAN>\n" );
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