document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=304707>Question 304707</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the measure of the second angle of a triangle is seven more than twice the measure of the first. the third angle is fifteen less than the first. find the meausres of all of the angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218199 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218199\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the first angle be x deg\r<BR>\n" );
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document.write( "The second angle = 2x+7\r<BR>\n" );
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document.write( "Third angle = x-15\r<BR>\n" );
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document.write( "The sum of all 3 angles = 180 deg.\r<BR>\n" );
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document.write( "x+2x+7+x-15= 180 \r<BR>\n" );
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document.write( "4x-8 =180<BR>\n" );
document.write( "4x=188\r<BR>\n" );
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document.write( "x= 47 deg\r<BR>\n" );
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document.write( "2x+7= 101 deg\r<BR>\n" );
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document.write( "Third angle = 32 deg\r<BR>\n" );
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document.write( "Ananth </SPAN>\n" );
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