document.write( "Question 35691: 1/x + 1/y = 1/2\r
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Algebra.Com's Answer #21819 by rapaljer(4671)\"\" \"About 
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To solve for either x or y, the first step is to clear the fractions by multiplying both sides by the LCD which is \"2xy\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2Fx+%2B+1%2Fy+=+1%2F2\"
\n" ); document.write( "\"2xy%2A%281%2Fx%29+%2B+2xy%2A%281%2Fy%29++=+2xy%2A%281%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"2y+%2B+2x+=+xy+\"\r
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\n" ); document.write( "\n" ); document.write( "Now, to solve for x, get all the x terms on one side by subtracting 2x from each side:
\n" ); document.write( "\"2y+=+xy+-+2x\"\r
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\n" ); document.write( "\n" ); document.write( "Factor the x, so as to get the x's all in one place:
\n" ); document.write( "\"2y+=+x%28y-2%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by (y-2):
\n" ); document.write( "\"%282y%29%2F%28y-2%29+=+%28x%2A%28y-2%29%29%2F%28y-2%29\"
\n" ); document.write( "\"%282y%29%2F%28y-2%29+=+x\"\r
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\n" ); document.write( "\n" ); document.write( "NOW, to solve for y in terms of x, go back to the equation \"2y+%2B+2x+=+xy+\".\r
\n" ); document.write( "\n" ); document.write( "To solve for y, get all the y terms on one side by subtracting 2y from each side:
\n" ); document.write( "\"2x+=+xy+-+2y\"\r
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\n" ); document.write( "\n" ); document.write( "Factor the y, so as to get the y's all in one place:
\n" ); document.write( "\"2x+=+y%28x-2%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by (x-2):
\n" ); document.write( "\"%282x%29%2F%28x-2%29+=+%28y%2A%28x-2%29%29%2F%28x-2%29\"
\n" ); document.write( "\"%282x%29%2F%28x-2%29+=+y\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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