document.write( "Question 304636: if the area of a rectangle is 48 and the length is 4 less than twice the width,what is the measure of the width? \n" ); document.write( "
Algebra.Com's Answer #218187 by checkley77(12844)\"\" \"About 
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A=LW
\n" ); document.write( "L=2W-4
\n" ); document.write( "48=(2W-4)W
\n" ); document.write( "48=2W^2-4W
\n" ); document.write( "2W^2-4W-48=0
\n" ); document.write( "2(W^2-2W-24)=0
\n" ); document.write( "2(W-6)(W+4)=0
\n" ); document.write( "W-6=0
\n" ); document.write( "W=6 ANS.
\n" ); document.write( "L=2*6-4=12-4=8 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "48=(2*6-4)6
\n" ); document.write( "48=(12-4)6
\n" ); document.write( "48=8*6
\n" ); document.write( "48=48
\n" ); document.write( "
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