document.write( "Question 304636: if the area of a rectangle is 48 and the length is 4 less than twice the width,what is the measure of the width? \n" ); document.write( "
Algebra.Com's Answer #218187 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! A=LW \n" ); document.write( "L=2W-4 \n" ); document.write( "48=(2W-4)W \n" ); document.write( "48=2W^2-4W \n" ); document.write( "2W^2-4W-48=0 \n" ); document.write( "2(W^2-2W-24)=0 \n" ); document.write( "2(W-6)(W+4)=0 \n" ); document.write( "W-6=0 \n" ); document.write( "W=6 ANS. \n" ); document.write( "L=2*6-4=12-4=8 ANS. \n" ); document.write( "PROOF: \n" ); document.write( "48=(2*6-4)6 \n" ); document.write( "48=(12-4)6 \n" ); document.write( "48=8*6 \n" ); document.write( "48=48 \n" ); document.write( " |