document.write( "Question 304689: Can you please help me with this problem?\r
\n" ); document.write( "\n" ); document.write( "Winter wheat. While finding the amount of seed needed
\n" ); document.write( "to plant his three square wheat fields, Hank observed that
\n" ); document.write( "the side of one field was 1 kilometer longer than the side
\n" ); document.write( "of the smallest field and that the side of the largest field
\n" ); document.write( "was 3 kilometers longer than the side of the smallest field.
\n" ); document.write( "If the total area of the three fields is 38 square kilometers,
\n" ); document.write( "then what is the area of each field? \n" ); document.write( "
Algebra.Com's Answer #218180 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
x^2+(x+1)^2+(x+3)=38
\n" ); document.write( "x^2+x^2+2x+1+x^2+6x+9=38
\n" ); document.write( "3x^2+8x+10-38=0
\n" ); document.write( "3x^2+8x-28=0
\n" ); document.write( "(3x+14)(x-2)=0
\n" ); document.write( "x-2=0
\n" ); document.write( "x=2 km^2 ans. for the sides of the smaller field.
\n" ); document.write( "2+1=3 km^2 ans. for the sides of the second field.
\n" ); document.write( "2+3=5 km^2 ans. for the sides of the largest field.
\n" ); document.write( "Proof:
\n" ); document.write( "2^2+3^2+5^2=38
\n" ); document.write( "4+9+25=38
\n" ); document.write( "38=38
\n" ); document.write( " \n" ); document.write( "
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