document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=304665>Question 304665</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the promblem is very confusing\r<BR>\n" );
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document.write( "The average annual undergraduated tution and fee charges C, in dollars for a certain 4 yr college for academic years 2000-2001 through 2005-2006 can be estmiated by the equation C=29.7x^2 +314.4x +3467.1, where x is the number of years after the 2000-2001 scademic year. assuming the model will remain valid beyond 2005-2006, in which academic YEAR will tution and fee charges be 8000? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218159 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218159\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The average annual undergraduated tution and fee charges C, in dollars for a certain 4 yr college for academic years 2000-2001 through 2005-2006 can be estmiated by the equation C=29.7x^2 +314.4x +3467.1, where x is the number of years after the 2000-2001 scademic year. assuming the model will remain valid beyond 2005-2006, in which academic YEAR will tution and fee charges be 8000?<BR>\n" );
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document.write( "C(x) = 29.7x^2 +314.4x +3467.1<BR>\n" );
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document.write( "Solve 29.7x^2 + 314.4x + 3467.1 = 8000<BR>\n" );
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document.write( "29.7x^2 + 314.4x - 4532.9 = 0<BR>\n" );
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document.write( "I graphed the quadratic and found a positive<BR>\n" );
document.write( "solution at x = 8.1472<BR>\n" );
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document.write( "Year = 2000+8.1472 means academic year 2009-10<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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