document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=304541>Question 304541</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 70. One number is ten more than twice the other number. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218131 by </B><A HREF=/tutors/aboutme.mpl?userid=london+maths+tutor><B>london maths tutor(243)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=london+maths+tutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=london+maths+tutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218131\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let one number be x and the other be y\r<BR>\n" );
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document.write( "x = 2y + 10 ... equation 1\r<BR>\n" );
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document.write( "x + y = 70 ... equation 2\r<BR>\n" );
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document.write( "put equation 1 into equation 2 \r<BR>\n" );
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document.write( "(2y + 10) + y = 70\r<BR>\n" );
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document.write( "3y = 70 - 10 \r<BR>\n" );
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document.write( "3y = 60 \r<BR>\n" );
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document.write( "y = 60/3<BR>\n" );
document.write( "y = 20 \r<BR>\n" );
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document.write( "x = 2(20) + 10 = 40 + 10 = 50 \r<BR>\n" );
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document.write( "Answer: the numbers are 50 and 20  \r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );