document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4632>Question 4632</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i^91=?<BR>\n" );
document.write( "This question was asked previously (question 3340), and the given soluttion was to find where i^91 came in the cycle of i. However I learned another way to do it, and I was wondering if it is correct.<BR>\n" );
document.write( "Take the given question i^91:<BR>\n" );
document.write( "i^91 = i^90 + 1<BR>\n" );
document.write( "     = i^90 * i^1<BR>\n" );
document.write( "     = (i^2)^45*i^1<BR>\n" );
document.write( "     = -1^45 * i^1<BR>\n" );
document.write( "     = -1 * i<BR>\n" );
document.write( "     = -i<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2181 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2181\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Since 91 = 3 mod 4<BR>\n" );
document.write( " i^91  = i^3 = -i<BR>\n" );
document.write( " <BR>\n" );
document.write( " That's the whole story for this kind of baby math.<BR>\n" );
document.write( " Forget any solution more than two lines.<BR>\n" );
document.write( " If you still confused, think more and work hard\r<BR>\n" );
document.write( "\n" );
document.write( " Kenny </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );