document.write( "Question 304523: While hiking the Peralta Trail to Wheeler’s Needle and back, Rick spent 60% of his time walking uphill to Wheeler’s Needle and 40% of his time returning by the same trail. If he averaged 2 miles per hour uphill, what was his average speed for the round-trip?\r
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document.write( "A. 2 1/3 mph B. 2.25 mph C. 2.4 mph D. 2.5 mph E. 2.6 mph
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Algebra.Com's Answer #218094 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Rick spent 60% of his time walking uphill to Wheeler’s Needle and 40% of his time returning by the same trail. \n" ); document.write( "If he averaged 2 miles per hour uphill, what was his average speed for the round-trip? \n" ); document.write( ": \n" ); document.write( "Let t = total time for the round trip \n" ); document.write( "then using the distance equation dist = speed * time \n" ); document.write( "2(.6t )= 1.2t distance one way \n" ); document.write( ": \n" ); document.write( "Find the speed (s) down hill, using a distance equation \n" ); document.write( "s(.4t) = 1.2t \n" ); document.write( ".4st = 1.2t \n" ); document.write( "Divide by t \n" ); document.write( ".4s = 1.2 \n" ); document.write( "s = \n" ); document.write( "s = 3 mph down hill speed \n" ); document.write( ": \n" ); document.write( "Find the average speed (a) using a time equation \n" ); document.write( " \n" ); document.write( "multiply by 6a \n" ); document.write( "3a(.6t) + 2a(.4t) = 6t \n" ); document.write( ": \n" ); document.write( "1.8at + .8at = 6t \n" ); document.write( "2.6at = 6t \n" ); document.write( "Divide both sides by t \n" ); document.write( "2.6a = 6 \n" ); document.write( "a = \n" ); document.write( "a = 2.31 mph is the average speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution \n" ); document.write( " \n" ); document.write( "Divide thru by t \n" ); document.write( " \n" ); document.write( ".3 + .133 = .433\r \n" ); document.write( "\n" ); document.write( ": \n" ); document.write( "I can't seem to come up with one the given solutions??? \n" ); document.write( " |