document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=304579>Question 304579</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 44 cm. one side is 12 cm longer than the other side. find the lengths of the sides. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218090 by </B><A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><B>blwinbbbles(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=blwinbbbles><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218090\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> l = length  w = width\r<BR>\n" );
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document.write( "Let's write what we know\r<BR>\n" );
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document.write( "l = w + 12  ....one side is 12 cm longer that the other<BR>\n" );
document.write( "2l + 2w = 44 ....since you add up all sides for the perimeter and there are 2 lengths and 2 widths\r<BR>\n" );
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document.write( "now use substitution since we know l = w + 12<BR>\n" );
document.write( "2(w + 12) + 2w =44<BR>\n" );
document.write( "2w + 24 + 2w = 44<BR>\n" );
document.write( "4w + 24 = 44  subtract 24 from both sides<BR>\n" );
document.write( "4w = 20  divide by 4<BR>\n" );
document.write( "w = 5  \r<BR>\n" );
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document.write( "now that you know what w is: <BR>\n" );
document.write( "l = 5 + 12  (first equation)<BR>\n" );
document.write( "l = 17  so now you know\r<BR>\n" );
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document.write( "w = 5cm and l = 17cm<BR>\n" );
document.write( " </SPAN>\n" );
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