document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=304548>Question 304548</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3/8 + 10/16 * (-8)^1/3   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218051 by </B><A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><B>blwinbbbles(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=blwinbbbles><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218051\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a fraction as an exponetial indicates a root...so that 1/2 is the square root, 1/3 is the cubic root, 1/4 is the 4th root...etc.\r<BR>\n" );
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document.write( "so start by simplifing the equations\r<BR>\n" );
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document.write( "3/8 + 10/16 times the cubic root of -8\r<BR>\n" );
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document.write( "6/16 + 10/16 times -2 (-2 is the cubic root of -8)  \r<BR>\n" );
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document.write( "16/16 * -2<BR>\n" );
document.write( "1 * -2 = -2\r<BR>\n" );
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document.write( "So the answer is -2 </SPAN>\n" );
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