document.write( "Question 304503: the sum of three numbers id 138. the second is 5 more than the smallest and the third is 10 more than the smallest. find the numbers.
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Algebra.Com's Answer #218050 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Three numbers: x, y, z, (z is the largest) \n" ); document.write( ": \n" ); document.write( "the sum of three numbers is 138. \n" ); document.write( "x + y + z = 138 \n" ); document.write( ": \n" ); document.write( "the second is 5 more than the smallest \n" ); document.write( "y = x + 5 \n" ); document.write( ": \n" ); document.write( "and the third is 10 more than the smallest. \n" ); document.write( "z = x + 10 \n" ); document.write( ": \n" ); document.write( "find the numbers. \n" ); document.write( "x + y + z = 138 \n" ); document.write( "Substitute \n" ); document.write( "x + (x+5) + (x+10) = 138 \n" ); document.write( ": \n" ); document.write( "3x + 15 = 138 \n" ); document.write( "3x = 138 - 15 \n" ); document.write( "3x = 123 \n" ); document.write( "x = \n" ); document.write( "x = 41 \n" ); document.write( "then \n" ); document.write( "y = 46 \n" ); document.write( "and \n" ); document.write( "z = 51 \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check: 41 + 46 + 51 = 138 \n" ); document.write( " |