document.write( "Question 304420: Soybean meal is 14% protein, cornmeal is 7% protein. How many pounds of each should be mixed together in order to get a 280lb mixture that is 12% protein? \n" ); document.write( "

Algebra.Com's Answer #217993 by mananth(16946) $\"\"$ $\"About$

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Soybean meal is 14% protein, cornmeal is 7% protein. How many pounds of each should be mixed together in order to get a 280lb mixture that is 12% protein? \r
\n" ); document.write( "\n" ); document.write( "soyabean - 14% protien\r
\n" ); document.write( "\n" ); document.write( "cornmeal - 7% protien\r
\n" ); document.write( "\n" ); document.write( "280 -12 %\r
\n" ); document.write( "\n" ); document.write( "Let soyabean required be x lbs\r
\n" ); document.write( "\n" ); document.write( "cornmeal will be 280-x lbs\r
\n" ); document.write( "\n" ); document.write( "0.14x+0.07(280-x)=0.12*280\r
\n" ); document.write( "\n" ); document.write( "0.14x+19.60-0.07x=33.60\r
\n" ); document.write( "\n" ); document.write( "0.07x = 33.60 -19.60\r
\n" ); document.write( "\n" ); document.write( "0.07x=14.00\r
\n" ); document.write( "\n" ); document.write( "x= 14/ 0.07\r
\n" ); document.write( "\n" ); document.write( "x= 200 pounds of soyabean\r
\n" ); document.write( "\n" ); document.write( "280-200 = 80 pounds of corn meal is required\r
\n" ); document.write( "\n" ); document.write( "Ananth\r
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