document.write( "Question 304321: Find two consecutive even intergers such that the sum of their recipricols is 9/40.\r
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Algebra.Com's Answer #217978 by checkley77(12844)\"\" \"About 
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1/x+1/(x+2)=9/40
\n" ); document.write( "(x+2+x)/x(x+2)=9/40
\n" ); document.write( "(2x+2)/(x^2+2x)=9/40 cross multiply
\n" ); document.write( "9(x^2+2x)=40(2x+2)
\n" ); document.write( "9x^2+18x=80x+80
\n" ); document.write( "9x^2+18x-80x-80=0
\n" ); document.write( "9x^2-62x-80=0
\n" ); document.write( "(9x+10)(x-8)=0
\n" ); document.write( "9x-10=0
\n" ); document.write( "9x=-10
\n" ); document.write( "x=-10/9
\n" ); document.write( "x=-1.111 ans.
\n" ); document.write( "x-8=0
\n" ); document.write( "x=8 ans.
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