document.write( "Question 304360: I have to figure out how much no fat yogurt should be mixed with regular yogurt to obtain 60 pounds of low fat yogurt.
\n" ); document.write( "I have 3% fat yogurt blends with no-fat yogurt that yields a 1%low fat yogurt.\r
\n" ); document.write( "\n" ); document.write( "I know that x60 is what I need to determine.
\n" ); document.write( ".03x is the 3%, .01 is the 1% which gives me 4% total lowfat yogurt. Then I divided that into the 60 needed and I came up with 17 pounds.
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Algebra.Com's Answer #217956 by richwmiller(17219)\"\" \"About 
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Not quite
\n" ); document.write( "We want to end up with 60 pounds of 1%
\n" ); document.write( "The no fat will have 0% fat that will be x
\n" ); document.write( "y will be how much of the 3% we add
\n" ); document.write( "x+y equals 60
\n" ); document.write( ".03*y=.01*(60)
\n" ); document.write( "x+y=60
\n" ); document.write( "y=20 x=40
\n" ); document.write( "check
\n" ); document.write( "3/100*20+40*0%=1/100*60
\n" ); document.write( "60/100+0=60/100
\n" ); document.write( ".6=.6
\n" ); document.write( "ok
\n" ); document.write( "another way to look at it is from the non fat view
\n" ); document.write( "1=100%\r
\n" ); document.write( "\n" ); document.write( ".97*y+1*x=60*.99
\n" ); document.write( "x+y=60
\n" ); document.write( "same answers
\n" ); document.write( "y=20 x=40
\n" ); document.write( "40 pounds of non fat \n" ); document.write( "
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