document.write( "Question 304337: mike's age is three-fourths of mary's age. in 5 years mike's age will be 7/9 mary's age . how old is mike now \n" ); document.write( "
Algebra.Com's Answer #217949 by checkley77(12844)\"\" \"About 
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Mike=3x/4
\n" ); document.write( "Mary=x
\n" ); document.write( "(3x/4+5)=7/9(x+5)
\n" ); document.write( "3x/4+5=7(x+5)/9
\n" ); document.write( "3x/4+5=(7x+35)/9
\n" ); document.write( "(3x+5*4)/4=(7x+35)/9
\n" ); document.write( "(3x+20)/4=(7x+35)/9 cross multiply.
\n" ); document.write( "9(3x+20)=4(7x+35)
\n" ); document.write( "27x++180=28x+140
\n" ); document.write( "27x-28x=140-180
\n" ); document.write( "-x=-40
\n" ); document.write( "x=40 ans. for Mary's age now.
\n" ); document.write( "3*40/4=120/4=30 ans. for Mike's age now.
\n" ); document.write( "Proof:
\n" ); document.write( "30+5=7/9(40+5)
\n" ); document.write( "35=7/9*45
\n" ); document.write( "35=7*5
\n" ); document.write( "35=35
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