document.write( "Question 304337: mike's age is three-fourths of mary's age. in 5 years mike's age will be 7/9 mary's age . how old is mike now \n" ); document.write( "
Algebra.Com's Answer #217949 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! Mike=3x/4 \n" ); document.write( "Mary=x \n" ); document.write( "(3x/4+5)=7/9(x+5) \n" ); document.write( "3x/4+5=7(x+5)/9 \n" ); document.write( "3x/4+5=(7x+35)/9 \n" ); document.write( "(3x+5*4)/4=(7x+35)/9 \n" ); document.write( "(3x+20)/4=(7x+35)/9 cross multiply. \n" ); document.write( "9(3x+20)=4(7x+35) \n" ); document.write( "27x++180=28x+140 \n" ); document.write( "27x-28x=140-180 \n" ); document.write( "-x=-40 \n" ); document.write( "x=40 ans. for Mary's age now. \n" ); document.write( "3*40/4=120/4=30 ans. for Mike's age now. \n" ); document.write( "Proof: \n" ); document.write( "30+5=7/9(40+5) \n" ); document.write( "35=7/9*45 \n" ); document.write( "35=7*5 \n" ); document.write( "35=35 \n" ); document.write( " \n" ); document.write( " |