document.write( "Question 304041: find the area of the circle whose equation is: x^2-4x+y^2+12y-25=0\r
\n" ); document.write( "\n" ); document.write( "(hint: the equation for a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is the center and r is the radius)
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Algebra.Com's Answer #217863 by nerdybill(7384)\"\" \"About 
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find the area of the circle whose equation is: x^2-4x+y^2+12y-25=0
\n" ); document.write( "(hint: the equation for a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is the center and r is the radius)
\n" ); document.write( ".
\n" ); document.write( "\"+x%5E2-4x%2By%5E2%2B12y-25=0+\"
\n" ); document.write( "Complete the square:
\n" ); document.write( "\"+%28x%5E2-4x%2B__%29+%2B+%28y%5E2%2B12y%2B__%29+=+25+\"
\n" ); document.write( "\"+%28x%5E2-4x%2B4%29+%2B+%28y%5E2%2B12y%2B36%29+=+25%2B4%2B36+\"
\n" ); document.write( "\"+%28x-2%29%5E2+%2B+%28y%2B6%29%5E2+=+65+\"
\n" ); document.write( "From here we see that:
\n" ); document.write( "\"r%5E2=+65+\"
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\n" ); document.write( "\"Area+=+%28pi%29r%5E2\"
\n" ); document.write( "\"Area+=+%283.14%29%2865%29\"
\n" ); document.write( "\"Area+=+204.1+\" square units\r
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