document.write( "Question 304107: if k is a positive integer,what is the least value of k for which sqrt (5k/3) is an integer?\r
\n" ); document.write( "\n" ); document.write( "A 3 b 5 c 15 d 25 e 60
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Algebra.Com's Answer #217860 by josmiceli(19441)\"\" \"About 
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In order for \"sqrt%285k%2F3%29\" to be an integer, \"k\" must be divisible by \"3\"
\n" ); document.write( "I'll create a new variable \"k+=+3j\" and I have
\n" ); document.write( "\"sqrt%285j%29\" which must be an integer, so \"5j\" must be a perfect square.
\n" ); document.write( "\"j+=+5\" gives me the smallest square
\n" ); document.write( "\"k+=+3j\"
\n" ); document.write( "\"k+=+3%2A5\"
\n" ); document.write( "\"k+=+15\"
\n" ); document.write( "The answer is c
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