document.write( "Question 304073: Could u please answer this... thanks...\r
\n" ); document.write( "\n" ); document.write( "The sum of the ages of the father and his son is 99. If the age of the son is added to the inverted age of the father the sum is 72. if the inverted age of the son is subtracted from the age of the father, the difference is 22. what are their ages?
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Algebra.Com's Answer #217848 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let 10x+y=age of father
\n" ); document.write( "Inverted age of father=10y+x
\n" ); document.write( "Then 99-(10x+y)=age of son, or
\n" ); document.write( "99-10x-y=(90-10x)+(9-y)=age of son
\n" ); document.write( "Inverted age of son=(90-10y)+(9-x)
\n" ); document.write( "Now we are told that:
\n" ); document.write( "10y+x+90-10x+9-y=72 simplify
\n" ); document.write( "9y-9x=-27 or
\n" ); document.write( "x-y=3------------------eq1
\n" ); document.write( "and
\n" ); document.write( "10x+y-{(90-10y)+(9-x)}=22 simplify
\n" ); document.write( "10x+y-90+10y-9+x=22
\n" ); document.write( "11x+11y=121
\n" ); document.write( "x+y=11-----------------eq2
\n" ); document.write( "add eq1 and eq2 and we get:
\n" ); document.write( "2x=14
\n" ); document.write( "x=7
\n" ); document.write( "substitute x=7 into eq2 and we get:
\n" ); document.write( "7+y=11
\n" ); document.write( "y=4
\n" ); document.write( "so father's age is 10x+y=10*7+4=74
\n" ); document.write( "and son's age is 99-74=25\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "47+25=72
\n" ); document.write( "72=72
\n" ); document.write( "and
\n" ); document.write( "74-52=22
\n" ); document.write( "22=22\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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