document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=304079>Question 304079</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am completely in the dark with application problems,,,,,,<BR>\n" );
document.write( "here is one,,,,<BR>\n" );
document.write( "the power rating P in watts, of an electrical appliance is determined bu p=IxV, where I is the cuurent in amperes and V is measured in volts.<BR>\n" );
document.write( "A. A kitchen requires 30 amps of current and the coltage in the house is 115 volts, wht is the wattage of the kitchen?\r<BR>\n" );
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document.write( "b. Solve for I;for V.\r<BR>\n" );
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document.write( "need answer by tomorrow ,,,thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #217843 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=217843\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "the power rating P in watts, of an electrical appliance is determined bu p=IxV, where I is the cuurent in amperes and V is measured in volts.<BR>\n" );
document.write( "A. A kitchen requires 30 amps of current and the coltage in the house is 115 volts, wht is the wattage of the kitchen?\r<BR>\n" );
document.write( "\n" );
document.write( "b. Solve for I;for V.\r<BR>\n" );
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document.write( "p = I*V\r<BR>\n" );
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document.write( "P= 30 * 115 = 345 watts </SPAN>\n" );
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