document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=304081>Question 304081</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hello....<BR>\n" );
document.write( "plsss help me to solve this question\r<BR>\n" );
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document.write( "Q1'How much pure alcohol should be added to 400ml of a 15% strength to make its strength 32%?'\r<BR>\n" );
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document.write( "thank you to help me.....it is from my Olympiad workbook<BR>\n" );
document.write( "sir/mam plss help me... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #217841 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=217841\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> pure alcohol assume 100%\r<BR>\n" );
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document.write( "let the requirement be x\r<BR>\n" );
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document.write( "400 ml of 15% \r<BR>\n" );
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document.write( "total x+400 of 32%\r<BR>\n" );
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document.write( "1x+0.15*400= 0.32(x+400)\r<BR>\n" );
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document.write( "x+60 = 0.32x+128\r<BR>\n" );
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document.write( "x-0.32x= 68<BR>\n" );
document.write( "0.68x =68\r<BR>\n" );
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document.write( "x=68/0.68\r<BR>\n" );
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document.write( "=100 ml\r<BR>\n" );
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document.write( " </SPAN>\n" );
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