document.write( "Question 35645: please help me solve this using logarithms\r
\n" ); document.write( "\n" ); document.write( "8^(3x+4) = 3^x\r
\n" ); document.write( "\n" ); document.write( "stuff to the right of the ^'s are exponents....thanks!
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Algebra.Com's Answer #21782 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"8%5E%283x%2B4%29+=+3%5Ex\"\r
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\n" ); document.write( "\n" ); document.write( "First, take the ln of each side of the equation:
\n" ); document.write( "\"+ln++8%5E%283x%2B4%29+=+ln++3%5Ex\"\r
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\n" ); document.write( "\n" ); document.write( "By the third law of exponents, \"bring the exponents down\" to become coefficients:\r
\n" ); document.write( "\n" ); document.write( "\"%283x%2B4%29+%2A+ln+8+=+x%2A+ln+3\"\r
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\n" ); document.write( "\n" ); document.write( "Distributive property:\r
\n" ); document.write( "\n" ); document.write( "\"3x+%2A+ln+8+%2B+4+%2A+ln+8+=+x+%2A+ln+3\"\r
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\n" ); document.write( "\n" ); document.write( "Get all the x terms on one side and the non-x terms on the other side. You might want to subtract \"+3x+ln+8\" from each side:\r
\n" ); document.write( "\n" ); document.write( "\"+4%2A+ln+8+=+x+%2A+ln+3+-+3x%2A+ln+8\"\r
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\n" ); document.write( "\n" ); document.write( "Factor out the x on the left side in order to get the x in one place, so you can solve for x.
\n" ); document.write( "\"4%2A+ln+8+=+x%28ln+3+-+3+%2A+ln+8%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by \"+%28ln+3+-+3+%2A+ln+8%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%284%2A+ln+8%29%2F%28+ln3+-+3+%2A+ln+8%29\"\r
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\n" ); document.write( "\n" ); document.write( "Calculate with a calculator: x = -1.618 approximately. \r
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\n" ); document.write( "\n" ); document.write( "Thank you so much for this problem!! I could put it on my final exam for College Algebra next week!!\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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