document.write( "Question 303956: log2 (x + 4) = 3 + log2 (x - 5)\r
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document.write( "Please help!!!!!! Thank you so much!!!!!!! You guys are the best!!!!!!! \n" );
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Algebra.Com's Answer #217758 by nerdybill(7384) You can put this solution on YOUR website! log2 (x + 4) = 3 + log2 (x - 5) \n" ); document.write( "log2 (x + 4) - log2 (x - 5) = 3 \n" ); document.write( "log2 (x + 4)/(x - 5) = 3 \n" ); document.write( "(x + 4)/(x - 5) = 2^3 \n" ); document.write( "(x + 4)/(x - 5) = 8 \n" ); document.write( "(x + 4) = 8(x - 5) \n" ); document.write( "x + 4 = 8x - 40 \n" ); document.write( "x + 44 = 8x \n" ); document.write( "44 = 7x \n" ); document.write( "44/7 = x \n" ); document.write( "6.2857 = x\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |