document.write( "Question 35539: Solve the equation and atate any extraneous solutions. Thanks!\r
\n" ); document.write( "\n" ); document.write( "2y/ y - 4 - 3/ 5 = 3
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Algebra.Com's Answer #21771 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"%282y%29%2F%28+y+-+4%29+-+3%2F+5+=+3\"\r
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\n" ); document.write( "\n" ); document.write( "Start by adding \"3%2F5\" to each side of the equation:
\n" ); document.write( "\"%282y%29%2F%28+y+-+4%29++=+3%2B3%2F5+\"
\n" ); document.write( "\"%282y%29%2F%28+y+-+4%29++=+18%2F5+\"\r
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\n" ); document.write( "\n" ); document.write( "Now, since \"a%2Fb=c%2Fd\" means the same as \"a%2Ad=b%2Ac\", it follows that
\n" ); document.write( "\"%282y%29%2F%28+y+-+4%29++=+18%2F5+\" means that \"10y+=+18%28y-4%29+\"\r
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\n" ); document.write( "\n" ); document.write( "So, \"10y+=+18y+-+72\"
\n" ); document.write( "\"-8y+=+-72\"
\n" ); document.write( "\"y=+9\"\r
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\n" ); document.write( "\n" ); document.write( "This value of y does NOT make any denominators zero, so there are no extraneous roots. However, it's easy to check by substituting y=9 in the original equation:
\n" ); document.write( "\"%282y%29%2F%28+y+-+4%29+-+3%2F+5+=+3\"
\n" ); document.write( "\"%282%2A9%29%2F%28+9+-+4%29+-+3%2F+5+=+3\"
\n" ); document.write( "\"18%2F5+-+3%2F5+=+3\"
\n" ); document.write( "\"15%2F5+=+3\"\r
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\n" ); document.write( "\n" ); document.write( "It checks!!\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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