document.write( "Question 275186: can you find a two digit number that is twice as big as tha two digits multiplied together \n" ); document.write( "
Algebra.Com's Answer #217694 by JBarnum(2146)\"\" \"About 
You can put this solution on YOUR website!
first off this isnt an age problem
\n" ); document.write( "but i will do it anyway
\n" ); document.write( "(i.e. 37=3(10)+7 so if 3=x and 7=y then 10x+y=37)
\n" ); document.write( "a=10x+y
\n" ); document.write( "2a=xy
\n" ); document.write( "\"2%2810x%2By%29=10xy\"
\n" ); document.write( "\"%2820x%2B2y%29=xy\"
\n" ); document.write( "well good luck
\n" ); document.write( "5*5=25*2=50 no
\n" ); document.write( "6*4=24*2=48 no
\n" ); document.write( "2*3=6*2=12 no
\n" ); document.write( "2*8=16*2=32 no
\n" ); document.write( "2*6=12*2=24 no
\n" ); document.write( "2*5=10*2=20 no
\n" ); document.write( "3*4=12*2=24 no
\n" ); document.write( "3*6=18*2=36 yes wooot i found it
\n" ); document.write( "the number is 36
\n" ); document.write( "xy=(1/2)(10x+y)\r
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