document.write( "Question 303783: find the equation for the line tangent in y=mx+b form. f(x)=sqrt (x)/5 at (4,2/5) \n" ); document.write( "
Algebra.Com's Answer #217661 by Alan3354(69443)\"\" \"About 
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\"y+=+sqrt%28x%29%2F5\"
\n" ); document.write( "y' = \"%281%2F2%29x%5E%28-1%2F2%29%2F5\"
\n" ); document.write( "y' = \"1%2F%2810sqrt%28x%29%29\"
\n" ); document.write( "At x = 4, y = 2/5, y' = 1/20 = m
\n" ); document.write( "---------------
\n" ); document.write( "2/5 = (1/20)*4 + b
\n" ); document.write( "b = 1/5
\n" ); document.write( "--> y = (1/20)x + 1/5
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