document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=303770>Question 303770</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I know when do go up or down on the graph? Example. 2x + 3y = 6 Another, 2x - 3y = 6<BR>\n" );
document.write( "I hope I am making myself clear because I myself get confused. <BR>\n" );
document.write( "Thank you. Benita  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #217654 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=217654\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve for y.<BR>\n" );
document.write( "2x + 3y = 6 --> y = (-2/3)x + 2<BR>\n" );
document.write( "The coefficient of x is the slope, m = -2/3<BR>\n" );
document.write( "Negative slope goes douwn to the right, \  like that.<BR>\n" );
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document.write( "Another, 2x - 3y = 6 --> y = (2/3)x - 2<BR>\n" );
document.write( "m = +2/3<BR>\n" );
document.write( "Positive slopes go up to the right, / like that.\r<BR>\n" );
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