document.write( "Question 303652: the width of a rectangle is 5 inches shorter than the length and that the perimeter or the rectangle is 50 inches. set up and equation for the perimeter involving the length. solve this equation algebraically to find the length and width.
\n" ); document.write( "Thank-you
\n" ); document.write( "Shirley Sims
\n" ); document.write( "shirleysims174@aol.com \n" ); document.write( "
Algebra.Com's Answer #217644 by ankor@dixie-net.com(22740)\"\" \"About 
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the width of a rectangle is 5 inches shorter than the length and that the
\n" ); document.write( "W = L - 5
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\n" ); document.write( " perimeter or the rectangle is 50 inches.
\n" ); document.write( "2L + 2W = 50
\n" ); document.write( ":
\n" ); document.write( "set up an equation for the perimeter involving the length.
\n" ); document.write( "Replace W with (L-5)
\n" ); document.write( "2L + 2(L-5) = 50
\n" ); document.write( "solve this equation algebraically to find the length and width.
\n" ); document.write( "2L + 2L - 10 = 50
\n" ); document.write( "4L = 50 + 10
\n" ); document.write( "4L = 60
\n" ); document.write( "L = \"60%2F4\"
\n" ); document.write( "L = 15 in is the lenght
\n" ); document.write( "then
\n" ); document.write( "W = L - 5
\n" ); document.write( "W = 15 - 5
\n" ); document.write( "W = 10 in is the width
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\n" ); document.write( "Check solution by finding the perimeter with these values for L & W
\n" ); document.write( "2(15) + 2(10) = 50\r
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