document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=303677>Question 303677</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one angle of a triangle measures 12 degrees. the second angle's measurement is five times the third. what is the measure of the third angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #217613 by </B><A HREF=/tutors/aboutme.mpl?userid=graphmatics><B>graphmatics(170)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=graphmatics><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=graphmatics><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=217613\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Express the first, second, and third angles of the triangle be expressed as x, y, and Z. From the first sentence x=12. From the second sentence y=5z. For triangles the sum of the angles of a triangle is 180. So we get three linear equations\r<BR>\n" );
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document.write( "x = 12<BR>\n" );
document.write( "y = 5z<BR>\n" );
document.write( "x+y+z = 180\r<BR>\n" );
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document.write( "Put the expressions for x and y fron the first and second equations into the third equation to get\r<BR>\n" );
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document.write( "12+5z+z = 180<BR>\n" );
document.write( "6z = 180-12<BR>\n" );
document.write( "6z = 168\r<BR>\n" );
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document.write( "So the third angle measurement, z, is\r<BR>\n" );
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document.write( "z=28. </SPAN>\n" );
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