document.write( "Question 35547: solve: x=sqrt3x+13-5=\r
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Algebra.Com's Answer #21760 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"+x=sqrt%283x%2B13%29-5\"\r
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\n" ); document.write( "\n" ); document.write( "Start by adding +5 to each side:
\n" ); document.write( "\"+x%2B5+=sqrt%283x%2B13%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Next, square both sides:
\n" ); document.write( "\"+%28x%2B5%29%5E2+=+%28sqrt%283x%2B13%29%29%5E2\"
\n" ); document.write( "\"+x%5E2%2B10x+%2B+25+=+3x%2B13+\"\r
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\n" ); document.write( "\n" ); document.write( "This is quadratic, so set it equal to zero and factor! By the way, it ALWAYS factors in radical equations like this!\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+7x+%2B+12+=+0\"
\n" ); document.write( "\"%28x%2B3%29%28x%2B4%29+=+0\"
\n" ); document.write( "\"x=-3\" or \"x=+-4\"\r
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\n" ); document.write( "\n" ); document.write( "However, these answers are NOT guaranteed! They must be checked in the original equation:\r
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\n" ); document.write( "\n" ); document.write( "Check x = -3
\n" ); document.write( "\"+x=sqrt%283x%2B13%29-5\"
\n" ); document.write( "\"+-3+=+sqrt%283%2A%28-3%29%2B13%29+-+5\"
\n" ); document.write( "\"+-3+=+sqrt%284%29+-+5\"
\n" ); document.write( "\"-3+=+2-5\"
\n" ); document.write( "It checks!!\r
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\n" ); document.write( "\n" ); document.write( "Check x = -4
\n" ); document.write( "\"+x=sqrt%283x%2B13%29-5\"
\n" ); document.write( "\"+-4+=+sqrt%283%2A%28-4%29%2B13%29+-+5\"
\n" ); document.write( "\"+-4+=+sqrt%281%29+-+5\"
\n" ); document.write( "\"-4+=+1-5\"
\n" ); document.write( "It also checks!!\r
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\n" ); document.write( "\n" ); document.write( "Final answer is x= -3 or x= -4.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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