document.write( "Question 303543: Jon recently drove to visit his parents who live 225 miles away. On his way there his average speed was 24 miles per hour faster than on his way home. If Jon spent a total of 10 hours driving, find the two rates. \n" ); document.write( "
Algebra.Com's Answer #217541 by mananth(16946)![]() ![]() You can put this solution on YOUR website! LET HIS SPEED ON HIS WAY HOME BE X MPH\r \n" ); document.write( "\n" ); document.write( "Time taken in the return journey = 225/x\r \n" ); document.write( "\n" ); document.write( "His speed while going was x+24\r \n" ); document.write( "\n" ); document.write( "time taken in forward journey 225/ x+24\r \n" ); document.write( "\n" ); document.write( "225/x + 225 / x+24 = 10 hours\r \n" ); document.write( "\n" ); document.write( "225(x+24)+225x= 10*x(x+24)\r \n" ); document.write( "\n" ); document.write( "225x+5400 +225x= 10x^2 +240x\r \n" ); document.write( "\n" ); document.write( "10x^2-210x-5400=0\r \n" ); document.write( "\n" ); document.write( "x^2-21x-540=0\r \n" ); document.write( "\n" ); document.write( "x^2-36x+15x-540=0\r \n" ); document.write( "\n" ); document.write( "x(x-36)+15(x-36)=0\r \n" ); document.write( "\n" ); document.write( "(x-36)(x+15)=0\r \n" ); document.write( "\n" ); document.write( "x= 36 mph on way home\r \n" ); document.write( "\n" ); document.write( "while going it was 36+24 = 60 mph\r \n" ); document.write( "\n" ); document.write( "Ananth\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |