document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=35324>Question 35324</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me to solve this: 3e^-x - 4 = 9<BR>\n" );
document.write( "thanks<BR>\n" );
document.write( "*Triston </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21752 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3e^-x - 4 = 9 original<BR>\n" );
document.write( "3e^-x = 13 add four<BR>\n" );
document.write( "e^-x = (13/3) divide by 3<BR>\n" );
document.write( "-x = ln (13/3) take natural log of each side<BR>\n" );
document.write( "x = - ln (13/3) multiply by negative one<BR>\n" );
document.write( "x is about -1.4663 </SPAN>\n" );
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