document.write( "Question 303501: at 2:00 p.m. a runner heads north on a highway jogging at 10mph. at 2:30 p.m. a driver heads north on the same highway to pick up the runner. if the car travels at 55 mph, how long will it take the driver to catch the runner? \n" ); document.write( "
Algebra.Com's Answer #217514 by mananth(16946)![]() ![]() You can put this solution on YOUR website! jogger runs at 10 mph\r \n" ); document.write( "\n" ); document.write( "so in half hour he goes 5 miles\r \n" ); document.write( "\n" ); document.write( "Let the distance from this 5 mile point to the point they meet be x\r \n" ); document.write( "\n" ); document.write( "time taken by jogger = x/10\r \n" ); document.write( "\n" ); document.write( "car travels at 55 mph\r \n" ); document.write( "\n" ); document.write( "it has to travel x+5 miles to catch up the jogger\r \n" ); document.write( "\n" ); document.write( "time car takes = x+5 / 55\r \n" ); document.write( "\n" ); document.write( "both these times are same\r \n" ); document.write( "\n" ); document.write( "x+5/55 = x/10\r \n" ); document.write( "\n" ); document.write( "10(x+5) = 55x\r \n" ); document.write( "\n" ); document.write( "10x+50 = 55x\r \n" ); document.write( "\n" ); document.write( "45x=50\r \n" ); document.write( "\n" ); document.write( "x= 50/45 =10/9\r \n" ); document.write( "\n" ); document.write( "time = distance / speed\r \n" ); document.write( "\n" ); document.write( "distance car goes = 10/9 +5 miles\r \n" ); document.write( "\n" ); document.write( "time = 55/9 / 55\r \n" ); document.write( "\n" ); document.write( "1/9 \r \n" ); document.write( "\n" ); document.write( "= 1 /9\r \n" ); document.write( "\n" ); document.write( "-= 1/9 *60 minutes\r \n" ); document.write( "\n" ); document.write( "the truck cathches up in 6.66 minutes\r \n" ); document.write( "\n" ); document.write( "ananth \n" ); document.write( " |