document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=303510>Question 303510</A>: <I><SPAN STYLE=\"word-break: break-all;\"> initially, a tank contains 20 gallons of 30% antifreeze solution. how many gallans of 80% antifreeze solution should be added to the tank in order to have the concentration of the antifreeze in the tank increase to 50%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #217512 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=217512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> initially, a tank contains 20 gallons of 30% antifreeze solution. how many gallans of 80% antifreeze solution should be added to the tank in order to have the concentration of the antifreeze in the tank increase to 50%?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "alcohol + alcohol = alcohol<BR>\n" );
document.write( "0.30*20 + 0.80*x = 0.50(20+x)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Multiply thru by 100 and solve for \"x\":<BR>\n" );
document.write( "30*20 + 80x = 50*20 + 50x<BR>\n" );
document.write( "30x = 20*20<BR>\n" );
document.write( "x = (2/3)*20<BR>\n" );
document.write( "x = 13 1/3 gallons (amt of 80% antifreeze needed in the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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