document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=303326>Question 303326</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you solve 10 over the sqaure root of 12? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #217432 by </B><A HREF=/tutors/aboutme.mpl?userid=user_dude2008><B>user_dude2008(1862)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=user_dude2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=217432\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \frac{\sqrt{10}}{\sqrt{12}} = \frac{\sqrt{10}\sqrt{12}}{\sqrt{12}\sqrt{12}} = \frac{\sqrt{120}}{12} = \frac{\sqrt{4*30}}{12} = \frac{\sqrt{4}*\sqrt{30}}{12} = \frac{2*\sqrt{30}}{12} = \frac{\sqrt{30}}{6}\">\r<BR>\n" );
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document.write( "Answer:  <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \frac{\sqrt{10}}{\sqrt{12}} = \frac{\sqrt{30}}{6}\">  </SPAN>\n" );
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