document.write( "Question 303310: log(base)6(2x-5)+1=log(base)6(7x+10) \n" ); document.write( "
Algebra.Com's Answer #217431 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"log%286%2C%282x-5%29%29%2B1=log%286%2C%287x%2B10%29%29\"
\n" ); document.write( "\"log%286%2C%282x-5%29%29-log%286%2C%287x%2B10%29%29=-1\"\r
\n" ); document.write( "\n" ); document.write( "\"log%286%2C%28%282x-5%29%2F%287x%2B10%29%29%29=-1\"
\n" ); document.write( "\"%282x-5%29%2F%287x%2B10%29=6%5E%28-1%29=1%2F6\"
\n" ); document.write( "\"6%282x-5%29=7x%2B10\"
\n" ); document.write( "\"12x-30=7x%2B10\"
\n" ); document.write( "\"5x=40\"
\n" ); document.write( "\"x=8\"
\n" ); document.write( "
\n" ); document.write( "
\n" );