document.write( "Question 303318: The area of a rectangle is 21sqft. What are the dimensions is the length is 5 less four times the width. \n" ); document.write( "
Algebra.Com's Answer #217426 by user_dude2008(1862)\"\" \"About 
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21=LW\r
\n" ); document.write( "\n" ); document.write( "L=4W-5\r
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\n" ); document.write( "\n" ); document.write( "21=(4W-5)W\r
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\n" ); document.write( "\n" ); document.write( "4W^2-5W-21=0\r
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\n" ); document.write( "\n" ); document.write( "(W-3)(4W+7)=0\r
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\n" ); document.write( "\n" ); document.write( "W-3=0 or 4W+7=0\r
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\n" ); document.write( "\n" ); document.write( "W=3 or W=-7/4 Ignore\r
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\n" ); document.write( "\n" ); document.write( "Answer: Width = 3, length = 7
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