document.write( "Question 297434: Wyatt is diving from 10-meter platform. His hight, H, in meters above the water when he is, X, meters away from the platform is given by the formula, H=-X²+2X+10. Approximately how far away from the platform is he when he enters the water? \n" ); document.write( "
Algebra.Com's Answer #217425 by JBarnum(2146)\"\" \"About 
You can put this solution on YOUR website!
this is not an age problem use quadratic formula to solve
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"-1x%5E2%2B2x%2B10+=+0\") has the following solutons:
\n" ); document.write( "
\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
\n" ); document.write( "
\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
\n" ); document.write( "
\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%282%29%5E2-4%2A-1%2A10=44\".
\n" ); document.write( "
\n" ); document.write( " Discriminant d=44 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-2%2B-sqrt%28+44+%29%29%2F2%5Ca\".
\n" ); document.write( "
\n" ); document.write( " \"x%5B1%5D+=+%28-%282%29%2Bsqrt%28+44+%29%29%2F2%5C-1+=+-2.3166247903554\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%282%29-sqrt%28+44+%29%29%2F2%5C-1+=+4.3166247903554\"
\n" ); document.write( "
\n" ); document.write( " Quadratic expression \"-1x%5E2%2B2x%2B10\" can be factored:
\n" ); document.write( " \"-1x%5E2%2B2x%2B10+=+-1%28x--2.3166247903554%29%2A%28x-4.3166247903554%29\"
\n" ); document.write( " Again, the answer is: -2.3166247903554, 4.3166247903554.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+-1%2Ax%5E2%2B2%2Ax%2B10+%29\"

\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );