document.write( "Question 303232: i need help with this prob please show work so i know what to do\r
\n" ); document.write( "\n" ); document.write( "log 2x^2= (log 2x)^2
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Algebra.Com's Answer #217342 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"log%28%282x%5E2%29%29=%28log%28%282x%29%29%29%5E2\"
\n" ); document.write( "I used Newton's method to find the roots of
\n" ); document.write( "\"f%28x%29=log%28%282x%5E2%29%29-%28log%28%282x%29%29%29%5E2\"
\n" ); document.write( "\"df%2Fdx=2%2Fx-%282%2Alog%282x%29%29%2Fx\"
\n" ); document.write( "and I started with a value of x=0.2.
\n" ); document.write( "A quick check in EXCEL showed that the zero was between x=0.7 and x=0.8.
\n" ); document.write( "After 20 iterations, I got
\n" ); document.write( "\"x=0.7292\"
\n" ); document.write( "Quick check to verify,
\n" ); document.write( "\"log%28%282%280.7292%29%5E2%29%29=log%28%282%280.7292%29%29%29%5E2\"
\n" ); document.write( "\"log%28%282%280.7292%29%5E2%29%29=log%28%282%280.7292%29%29%29%5E2\"
\n" ); document.write( "\"log%281.0634%29=%28log%281.4584%29%29%5E2\"
\n" ); document.write( "\"0.026697=%28.16387%29%5E2\"
\n" ); document.write( "\"0.026697=0.026856\"
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