document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34021>Question 34021</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My problem is:\r<BR>\n" );
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document.write( "The base of a right pyramid is a regular hexagon with sides of length 12 m.  The altitude of the pyramid is 9 m.  Find the total surface area of the pyramid.  \r<BR>\n" );
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document.write( "Thanks for your help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21734 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21734\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The base of a right pyramid is a regular hexagon with sides of length 12 m. The altitude of the pyramid is 9 m. Find the total surface area of the pyramid.					<BR>\n" );
document.write( "Thanks for your help					<BR>\n" );
document.write( "TOTAL SURFACE AREA=AREA OF HEXAGONAL BASE +6*AREA OF LATERAL TRIANGULAR FACE					<BR>\n" );
document.write( "AREA OF HEXAGON=6*A^2*SQRT(3)/4=6*12^2*SQRT(3)/4=374.132					<BR>\n" );
document.write( "LATERAL TRIANGULAR FACE HAS ALTITUDE OF 9 M. AND DISTANCE OF CENTRE FROM VERTEX OF BASE =12 M					<BR>\n" );
document.write( "HENCE LATERAL EDGE = SQRT (12^2+9^2)=SQRT(144+81)=15					<BR>\n" );
document.write( "AREA OF LATERAL TRIANGLE WITH SIDES 12,15 AND 15 IS GIVEN BY FORMULA SQRT{S(S-A)(S-B)(S-C)} WHERE S =(12+15+15)/2=21					<BR>\n" );
document.write( "AREA=SQRT{21(21-12)(21-15)(21-15)}=SQRT(21*9*6*6)=18SQRT(21)=					<BR>\n" );
document.write( "T.S.A.OF PYRAMID = 374.132+6*82.4864=869.0504 </SPAN>\n" );
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