document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=303249>Question 303249</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2a squared-9a-18<BR>\n" );
document.write( "this is Factoring Trinomials </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #217323 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=217323\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, multiply the first term by the third term, 2*(-18) = -36\r<BR>\n" );
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document.write( "You need to find two numbers that multiply to -36, but add up to -9.\r<BR>\n" );
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document.write( "List the factors of 36: 36 and 1, 12 and 3, 9 and 4, 6 and 6....\r<BR>\n" );
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document.write( "You should notice that 12 and 3 are the only pair that could add up to 9.\r<BR>\n" );
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document.write( "Now we will re-write the equation with these factors:\r<BR>\n" );
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document.write( "2a^2 -9a - 18<BR>\n" );
document.write( "2a^2 - 12a + 3a - 18\r<BR>\n" );
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document.write( "Now factor out the 2a from the first pair, and the 3 from the second pair.\r<BR>\n" );
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document.write( "2a(a-6) + 3(a-6)\r<BR>\n" );
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document.write( "Notice that the (a-6) terms are identical. Now re-arrange, combining the 2a and the 3:\r<BR>\n" );
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document.write( "(2a+3)(a-6)\r<BR>\n" );
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document.write( "Use F.O.I.L. to check that it is correct. It should equal 2a^2 -9a -18 </SPAN>\n" );
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